Poker Hand Analyzer Ein Überblick
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Here, v gets incremented by 0 because multiplying by o is a multiplication by 0. Some of you may have noticed that on the other side of the multiplication, is a division by 0.
Now some languages are able to optimize and not evaluate the rest of the expression if there is a multiplication by 0, but not JavaScript.
Instead, JavaScript evaluates the entire expression. JavaScript nicely coerces this operation result back to a 0 and finally adds 1. This is actually achieved as a series of additions.
The reason for this is that JavaScript only allows bit operation on integers. This means we can only set the lower 32 bits, but this strategy needs to set any of 52 bits.
I found this could be accomplished using addition. Since no bit would ever be set twice and the body expression would always yield a power of 2, it was safe to do this.
The remaining iterations set i within the range of which are the indexes of the card array cs. Each iteration, our bit offset o gets set to the appropriate offset using Math.
This is because JavaScript only allows bit shifting on integers. Even though the number is stored as a float, its bits can still be manipulated.
The expression in the body nicely bit shifts the desired nibble down to the four LSBs. Here it can easily be masked with 15 0xF.
Once the bits in question are isolated, 1 is added to the value. This has the effect of setting the next highest bit in the nibble. For example: becomes , becomes and becomes Lastly, this value is multiplied by the offset o to bring it back to the correct position.
The first operation is modulo division. If you figured it out earlier, this has the unique property of summing all the values of each nibble in the bit field.
The interesting part about it is that regardless of which cards you have, this operation will return the same value based on the unique count of card ranks recorded in the bit field.
These values actually fall within the range of 1 to 10 and can act as an index into our poker hands array. So far we have this:.
Arrays are 0-indexed so we will need to subtract 1 from the value of v. This is what we do in the next operation:. Since our bit field s has a bit set for each rank, a straight would have 5 bits set in sequence.
Note that a bit field with the 5 LSBs set is equal to This condition will be true if a straight exists. There is one exception and that is a straight with the Ace low.
Looking back to the examples shown earlier, this special case is shown as its bit field representation.
If we find that a straight exists, subtract 3 from the value of v. This covers the 1 needed for the 0-indexed array plus an additional 2.
Since a straight would only occur if no duplicates were found, the value of v begins as 5 and becomes 2 i. Our hands array now looks like this:. The final line of code is in place to make the last remaining adjustments.
The first comparison checks to see if we have a flush. JavaScript nicely coerces this boolean into an integer 0 for False and 1 for True.
If there is no flush , then the index in v is already correct and we simply subtract 0. If there is a flush , then this implies that the value in v could only be that of high card or a straight.
Subtracting 1 from these indexes turns high card into a flush and turns a straight into a straight flush. There is only one more type of flush remaining, the royal flush.
Since there is only one open position left in out hands array, it is now claimed and we add 5 to v to make the final adjustment.
Here is the final code all together:. Working out the details of this algorithm brought me into many areas of JavaScript and bit operations that I had never explored in the past.
Card Ranks cs. Bit Fields s. Value hex. Not Important. Click on a card on the table to return it to the deck. Odds are calculated as soon as enough cards are in play.
The position to receive the next card is highighted in red. Click on any card to highlight it. Poker Tools. Help Win : Tie :. Win : Tie :. Dead Cards.
X Click on a card in the deck to deal it. Get Started.
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